(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A 1.50 m high trampoline stores 50.0J or elastic potential energy as a 39.2Kg child lands on it. What is the maximum speed the child will reach as he is propelled vertically into the air and how high above the ground will he reach before he lands again?

2. Relevant equations

Not sure what it means :/

Ek = Ep

Ek=1/2*m*v^2

Ep=m*g*h

Ek= kinetic energy

Ep= potential energy

m=mass

v=speed

h=height

g=gravitational force (9.81m/s^2)

3. The attempt at a solution

v= [Square Root]((Ek)/(1/2)(m))

v= [Square Root]((50.0J)/(0.5)(39.2Kg))

v= 1.5971 m/s

v= 1.60 m/s <---- Maximum speed i think

h= (Ep)/(m*g)

h= (50.0J)/(39.2Kg)(9.81m/s^2)

h= 0.13002 m

h= 0.130 m <---- Maximum height i think

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# Homework Help: Kinetic and Potential Energy

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