Kinetic Energy After Some Time Has Elapsed

AI Thread Summary
A 5 kg ball is dropped from a height of 10 meters, and the initial velocity is calculated to be 14 m/s using the equation V^2=2gh. The kinetic energy (KE) is computed as 490 J with the formula KE=1/2mv^2. To find the kinetic energy after 1 second, the acceleration due to gravity (9.81 m/s^2) must be applied to determine the velocity at that time. The discussion emphasizes the importance of using the correct gravitational constant in calculations. The conversation concludes with a reminder to recalculate the velocity after 1 second to find the updated kinetic energy.
quido
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A balla of mass 5 kg is dropped from a height of 10 meters. What is the kinetic energy after 1 second has elapsed?First i found the velocity using this equation V^2=2gh = 14m/s

Then I used this equation to find Kinetic Energy KE=1/2mv^2 and got this 490 J.

But i don't know how to find KE after 1 second elapsed. Can anyone help me?
 
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quido said:
But i don't know how to find KE after 1 second elapsed.
Hint: What's the acceleration due to gravity?
 
Doc Al said:
Hint: What's the acceleration due to gravity?

That's the all information I have.
 
quido said:
That's the all information I have.
The acceleration due to gravity is a constant. Check your book. (Hint: It's used in that equation you posted earlier.)
 
oh right. You mean 9.81m/s^2.

I used that to find Velocity? Was it wrong ?
 
quido said:
oh right. You mean 9.81m/s^2.

I used that to find Velocity? Was it wrong ?
Yes, that's what I mean. Now use it to find velocity after 1 second.
 
Oh thanks a lot.
 
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