- #1
Jrlinton
- 134
- 1
Homework Statement
A 120 kg hoop rolls along a horizontal floor so that its center of mass has a speed of 0.240 m/s. How much work must be done on the hoop to stop it?
Homework Equations
I of hoop=MR^2
The Attempt at a Solution
KE=0.5*m*v^2+0.5*(mR^2)(v/R)^2
=0.5*120kg*.24^2m/s+0.5*(120kg*R^2)(.24m/s^2/R^2)
=6.912 J
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