Kinetic energy of two different masses (ratio)

Click For Summary
SUMMARY

The discussion centers on calculating the kinetic energy ratio of two masses (20kg and 40kg) pushed with the same force over the same distance. The initial calculations incorrectly used arbitrary values and the wrong formula, leading to a ratio of 2:1. The correct approach utilizes the work-energy theorem, stating that work (W = Fd) is equal for both masses when force and distance are constant, resulting in a kinetic energy ratio of 1:1. The error was primarily due to misunderstanding the relationship between work and kinetic energy.

PREREQUISITES
  • Understanding of kinetic energy formula (Ek = mv²/2)
  • Familiarity with the work-energy theorem (W = Fd)
  • Basic knowledge of Newton's second law (F = ma)
  • Ability to convert units of energy (Joules)
NEXT STEPS
  • Study the work-energy theorem in detail
  • Learn about unit conversions in physics, particularly energy
  • Explore the implications of force and distance on work done
  • Review examples of kinetic energy calculations with varying masses
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone preparing for exams involving mechanics and energy concepts.

alingy1
Messages
325
Reaction score
0

Homework Statement


Two masses, one of 20kg and the other of 40kg, are pushed using the same force on the same distance.
What is the ratio of the kinetic energy? (Kinetic energy of 20kg/kinetic energy of 40kg)


Homework Equations



Ek=mv^2
F=ma
v=at

The Attempt at a Solution



So, I found that the answer is 2/1. But the answer key says it's 1/1.
Here's my logic:
Let's say the constant force is 20N.
And that the time the force is applied is 3 seconds.

20kg:
F=ma
a=1m/s^2
v=3m/s
Ek=mv^2/2=90N

40kg:
F=ma
a=0,5m/s^2
v=1,5m/s
Ek=mv^2/2=45N

Ratio: 90/45=2/1

Why does the answer key say otherwise? Is my logic false somewhere? Please help. My exam is coming up soon.
 
Physics news on Phys.org
The error is in that you're using the wrong formulae and making up arbitrary values.

The formula to be used here is W = Fd (work = force × distance). Work is the same concept as energy. If you use that, you can see that the energy is the same for both, because if the Force and the distance are both the same, the work done on the masses (= their kinetic energy) must be the same as well.

Also, your units are wrong – energy is measured in Joules (J), not Newtons (N).
 
The problem says over the same distance not the same time. Anyway its not a good idea to assume values of anything.
What is definition of work? Do you know the work energy theorem?
 

Similar threads

Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
1K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 13 ·
Replies
13
Views
1K
Replies
7
Views
2K