Calculate Kinetic Energy of 50.5g Golf Ball at 26.5m Height

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To calculate the kinetic energy of a 50.5-g golf ball at its highest point of 26.5 m, the result is 28.0838075 J. For part b, the kinetic energy at a height of 20.48 m (6.02 m below the highest point) must be determined using the same principles. The equation 0 = mgh + mv^2/2 can be applied to find the speed at this lower height. By subtracting the potential energy at 20.48 m from the total energy, the kinetic energy can be calculated, allowing for the determination of the speed. This method effectively illustrates the conversion between potential and kinetic energy as the ball descends.
eanderson
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A 50.5-g golf ball is driven from the tee with an initial speed of 40.4 m/s and rises to a height of 26.5 m. (a) Neglect air resistance and determine the kinetic energy of the ball at its highest point. (b) What is its speed when it is 6.02 m below its highest point?

A: 28.0838075 J
b: ?

what do i do for part b?
 
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First find the kinetic energy at that height... do it the same way you did for part a...

when you have the kinetic energy, you can get speed.
 
0 = mgh + mv^2/2 right? This way find v.
 
For Part B he is right... Do the same thing except with a height of 20.48 instead. Just subtracting less Potential Energy since the ball is now gaining more Kinetic.
 
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Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
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