Kinetic Energy/work finding the distance

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To determine how far a 12 kg block sliding at 18 m/s will travel before slowing to 8 m/s under a 50 N opposing force, the Work-Energy Theorem is applied. The change in kinetic energy is calculated using the formula K.E. = 1/2mv^2. The work done by the opposing force is negative, as it acts against the block's motion. By equating the work done to the change in kinetic energy, the distance can be calculated. The solution indicates the distance is approximately 7.68 m, suggesting option (d) is the correct answer.
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A 12 kg block is sliding to the left across the floor at a speed of 18 m/s. Opposing the
motion is a 50 N force. How far (in m) will the object travel before its speed is reduced
to 8 m/s?
(a) 21.4
(b) 31.2
(c) 18.4
(d) 7.7
(e) none of these




2. Homework Equations [/b]

lost on how to find distance tho..

K.E. = 1/2mv^2


The Attempt at a Solution


I got d but not sure...i thouhght it was d 7.68 round up
1/2mv2-1/2vi
 
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You should be able to use the Work-Energy Theorem to solve this one.

ƩW=ΔKE

You know the change in the block's kinetic energy, and you know that friction does negative work. It does not say that there is any other force pushing the block along, so friction is the only force doing work on the block.

Since work is force x distance, this becomes a simple "plug and chug" problem.
 
Use the work-energy theorem. Since you know the change in kinetic energy, you can find the work done by the 50 N force, and from that, you can find the distance over which that force was applied.
 
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