Kinetic explanation of evaporation of boiling/Melting.

AI Thread Summary
The discussion centers on the kinetic explanation of evaporation and melting, specifically the role of latent heat in these processes. It clarifies that the latent heat supplied during evaporation contributes to the potential energy of escaping molecules, as well as the work needed to overcome atmospheric pressure. The conversation highlights the distinction between molecular kinetic energy and macroscopic potential energy, emphasizing that while individual molecules possess kinetic energy, their collective behavior at a macroscopic level involves potential energy for work. Additionally, it addresses the confusion regarding latent heat in melting, explaining that it increases the potential energy of molecular internal energy rather than solely raising kinetic energy. Overall, the discussion underscores the complexities of energy transformations during phase changes.
al_201314
Messages
116
Reaction score
0
Hi guys

I am slightly confuse about a statement in the kinetic explanation for evaporation as well as melting.

Firstly for the evaporation: "Thus the latent heat supplied in causing evaporation represents the potential energy gain of the escaping molecules plus the work needed to expand against the atmosphere"

I understand that the mean KE drops after some of the molecules go into the air and latent heat is supplied to maintain the mean KE. But how does this extra heat represent the gain in PE of the escaping molecules? My thought is that since the molecules have escaped, how does it gain PE?


Similary, how does the latent heat for melting being regarded as increasing the PE of component of the molecular internal energy? I would have thought that the extra heat would continue to raise the KE to increase the molecules' vibrations for melting.

Thanks for any explanation.
 
Physics news on Phys.org
al_201314 said:
Hi guys

I am slightly confuse about a statement in the kinetic explanation for evaporation as well as melting.

Firstly for the evaporation: "Thus the latent heat supplied in causing evaporation represents the potential energy gain of the escaping molecules plus the work needed to expand against the atmosphere"

I understand that the mean KE drops after some of the molecules go into the air and latent heat is supplied to maintain the mean KE. But how does this extra heat represent the gain in PE of the escaping molecules? My thought is that since the molecules have escaped, how does it gain PE?
Pressure x volume = (Force / Area) Volume = Force x distance = energy

It is a matter of semantics whether one refers to this energy as Potential Energy or Kinetic Energy. It is kinetic energy at the molecular level. But at the macroscopic level, PV represents stored energy that can be used (not completely) to do work (eg steam engine).

Similary, how does the latent heat for melting being regarded as increasing the PE of component of the molecular internal energy? I would have thought that the extra heat would continue to raise the KE to increase the molecules' vibrations for melting.
You are right if you are looking only at the molecular level. A moving molecule has only kinetic energy.

But at the macroscopic level, the translational Kinetic energy of the gas molecules give them an ability to perform work at the macroscopic level. If the molecules are stuck to each other and are merely vibrating, they do not have (much) ability to do PdV work.

AM
 
Thanks for the help!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top