Kinetic friction and lost mechanical energy

AI Thread Summary
An object sliding down a 30-degree incline at constant velocity experiences kinetic friction, which can be calculated using the equation µ = tan(θ). The discussion revolves around determining the mechanical energy lost due to friction, with participants noting that this loss is equal to the thermal energy generated. The rate of energy dissipation can be found by either calculating the friction force times displacement per unit time or from potential energy loss per unit time. However, confusion arises regarding the term "consistent velocity," which may imply a constant value, including zero, leading to no energy dissipation. Clarification is needed on the specific mechanical energy being referenced, as the kinetic energy remains unchanged while potential energy decreases.
hunbogi
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An Object slides with a consistent velocity down an incline that has a 30 degree angle.
I'm trying to find the kinetic friction and the ratio that the mechanical energy is lost on the way down.

I think I have already calculated µ with F(friction)= µmgcos(θ)=mgsin(θ) out comes Tan(θ) = µ
I think I did that correctly..
I'm struggling with the other part about the rate that the mechanical energy is lost. I would guess that it is not possible to get the answer in a number.
3.
I tried to us PE = mgh -friction = k2.
mgh - µmghcos(θ) = ½mv^2þ
not sure what my answer might look like in the end.
 
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I agree with you that u= tan(theta). As for the ratio- the ratio of mechanical energy lost to what? Thermal energy maybe?
 
It only says find the mechanical energy that is lost because of friction on the way down the incline.
I think U =mgs is the potential energy. energy on the end of the incline is K = ½mv^2
so I think the diffrent between the two is the friction force.
 
Ok so there is no ratio. I think your getting force and energy confused also. Be aware that force has units of Newtons= kg*m/s^2 and energy has units of Joules= N*m= kg*m^2/s^2. The mechanical energy lost is equal to the thermal energy generated. So if T is thermal energy then using conservation of energy set ΔKE+ΔPE+T= 0 and solve for T. btw this should probably not be posted in advanced physics
 
Okey thanks I will try that. New here so I didn't know where to post
 
Well, hello hunbogi, and welcome to PF :)

I suppose the consistent velocity is a constant velocity and the ratio is the rate, i.e. the mechanical energy loss per unit time.
There are two ways to find that rate:
One is friction force times displacement per unit time
Two is from potential energy loss per unit time
Answers should be the same
 
The rate of energy dissipation will depend on the velocity. Is the velocity given?
 
no it only gives the angle 30 degree and says the velocity is consistent
 
Consistent velocity does not make much sense. Is this a translation from another language?
If it's constant velocity, it can have any value, including zero. In which case there is no energy dissipation.
Something is missing and it may be due to translation.
 
  • #10
Sorry it is constant velocity. mixed up in translation
 
  • #11
Can you post the entire problem, as it is? Not just a summary.
 
  • #12
3.
An object slides with a constant velocity down an 30 degree incline
a) Find the friction force and find the ratio of the mechanical energy that is lost on the way down
 
  • #13
Oh, I think you want to say "the fraction of mechanical energy". This could make sense.
It may ask "What fraction of the mechanical energy is lost due to friction". Like, one half or 1/3 or 0.2.

Still does not seem completely alright. It is not clear what mechanical energy they are talking about.
The kinetic energy does not change. So the decrease in potential energy will be equal to the work of the friction force.
 
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