Kinetic theory and temperature in gases

AI Thread Summary
The discussion centers on the relationship between temperature and the average kinetic energy of gas particles, emphasizing that temperature in Kelvin is proportional to kinetic energy. A specific question is raised regarding the mean kinetic energy of a gas at two temperature points: 277°C and 827°C. The initial calculation suggests that the kinetic energy at 827°C is 2.28x10^21, derived from a proportional increase based on the temperature change. However, there is confusion regarding the conversion of temperatures, as 55K does not equal 277°C, indicating a potential error in the initial premise. The conversation highlights the importance of accurate temperature conversions in kinetic theory calculations.
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Homework Statement


Temperature of a gas (in kelvin) is proportional to the average kinetic temperature of its particles.

Question: The temperature of 55k (277C) to 1100k(827C). At 277C the mean kinetic energy of the gas is 1.14x10^20. What is it at 827C?

Homework Equations


kinetic energy= ½ x mass x (velocity)²

The Attempt at a Solution



55k to 1100k is x20. 1.14x10^20 x20=2.28x10^21.

Just want to check this is correct as I have an exam tormorrow.
 
Last edited:
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I'm fairly out of it because I'm pretty tired, but seems alright to me.
 
lukas86 said:
I'm fairly out of it because I'm pretty tired, but seems alright to me.

Alright, cheers mate.
 
How is 55K = 277C??
 
5k maybe? I just noticed that now...
 

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