Kinetics of a rigid body (conservation of energy)

AI Thread Summary
The discussion focuses on the conservation of energy in a system involving a spring and a rigid body. Participants analyze the vertical displacement and the use of the Pythagorean theorem to calculate spring extension. They emphasize the importance of expressing kinetic and potential energy in terms of relevant quantities and highlight the differences in using English (Imperial) units versus metric units. Questions arise about the potential energy contributions from the spring and the center of gravity of the rotating body. The conversation concludes with clarification on the role of gravitational potential energy in the context of the spring's position.
sseebbeekkk
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Homework Statement


eZTS4A6.jpg
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Homework Equations


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(1) (pink) Is it vertical displacement ?
* 4 - 2 (unstretched length of the spring) ?

(2) (blue) What does it mean ?
* I was thinking that maybe they used The Pythagorean theorem (62+42)=7,2 ≅ 7) but I'm not sure. Besides I don't understand why they used it.

3. Attempt

My reasoning: In general I think they are using this formula,
upload_2015-7-17_13-20-26.png

where in that case the left side is the initial state - the right side - the final state of the spring.
 

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I recommend setting it up carefully in terms of conservation of energy, expressing T and V in terms of all the relevant quantities (leaving as symbols), making simplifications, solving for the unknown (with symbols), and plugging in numbers at the end.
 
The 4-2 and 7-2 are both calculations of spring extension. In each case, 2 is the relaxed length. At the horizontal position, the total length is 4, so the extension is 4-2. After rotating 30 degrees, the total length is 4+6 sin(30)=7.
I don't like the way they divide the mass by 32.2 in the KE terms. It seems more natural to me to multiply by 32.2 in the other terms - it comes to the same thing, of course. Maybe their way is standard in this non-metric system. I have no background in it.
 
The English (Imperial) unit of mass is slugs. One obtains mass by dividing weight (lbs) by the acceleration of gravity (32.2 ft/s/s) to obtain the mass in slugs.

I thought ballistics was the last holdout still using English units for real physics.

https://en.wikipedia.org/wiki/English_Engineering_units
 
Dr. Courtney said:
The English (Imperial) unit of mass is slugs. One obtains mass by dividing weight (lbs) by the acceleration of gravity (32.2 ft/s/s) to obtain the mass in slugs.

I thought ballistics was the last holdout still using English units for real physics.

https://en.wikipedia.org/wiki/English_Engineering_units
Ok, thanks.
 
Thank you for help.

Dr. Courtney - is this equation correct ?

X0yeXaC.png
 
Is the only potential energy due to the spring?
 
If a spring is not stretched or compressed, then there is no elastic potential energy stored in it.

However in this case at the beggining the spring was stretched 2 metres (4-2=2), hence 1/2*k*s1^2

At the end, the spring was stretched 5 meters (7-2=5), hence 1/2*k*s2^2

'W' stands for: work of a weight -> WΔy= 50 * (1.5)
 
  • #10
I think the only potential energy is due to the spring. If the spring lies the ground then mgh=0
 
  • #11
sseebbeekkk said:
I think the only potential energy is due to the spring. If the spring lies the ground then mgh=0
The massive bar is rotating in a vertical plane. Are you saying its centre of gravity does not change in height?
 
  • #12
Ok, it does. Thanks.
 
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