Kinetics with Veloctiy/Acceleration Problem

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The discussion revolves around solving a velocity function v(t) = 3t - 11 for a particle's distance traveled over the interval from t = 0 to t = 5 seconds. The user initially calculates the velocity at t = 5 but realizes this does not represent the total distance traveled. They attempt to find the anti-derivative of the velocity function to calculate distance but encounter issues with their integration, leading to a negative result. The user is confused about the correct approach and how to properly evaluate the integral, as their answer differs from the one provided in the answer book. Clarification on integrating polynomials and evaluating definite integrals is needed to resolve the discrepancies.
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Hello, I need help on this following problem on velocity/acceleration

1. Homework Statement

The velocity function (in meters per second) is given for a particle moving along a line.

v(t)=3t-11, 0 (greater than or equal to) t (greater than or equal to) 5

Find the distance (in meters) traveled by the particle during the given time interval2. Homework Equations

v(t)=3t-11, 0 (greater than or equal to) t (greater than or equal to) 5

3. The Attempt at a Solution

I tried the following:
3(5)-11=4

But it isn't correct, can someone help me with this problem?

I know I have to find the anti-derivative of v(t).

How would I find t? Do I have to do the derivative of v(t) to find acceleration? Would that help me do this problem?

Can someone help me with this problem?

Thanks
 
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I tried the following:
3(5)-11=4

That's the velocity of the particle at t=5. It's not the total distance travelled.

I know I have to find the anti-derivative of v(t).

How would I find t? Do I have to do the derivative of v(t) to find acceleration? Would that help me do this problem?

The anti-derivative is just the integral. Do you know how to find the integral of a polynomial?
 
ideasrule said:
That's the velocity of the particle at t=5. It's not the total distance travelled.
The anti-derivative is just the integral. Do you know how to find the integral of a polynomial?

Yes. This is what I have so far and it's coming up negative:

3/2*t^2-11*t from 0 to 5, so 3/2*25-55 -0 = 125/2-55=-17.5

Whereas the answer book is showing: 137/6

So for some reason, my answer isn't totaling correctly
 
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