- #1

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- Thread starter Elliptic
- Start date

- #1

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- #2

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- #3

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But, how make Pm'(x) I don't understand(recurrent differentiation formula?)

- #4

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[itex]\displaystyle \frac{d}{dx}\left[(1-x^2)\frac{d}{dx}P(x)\right] = -\lambda P(x)[/itex]

where the eigenvalue [itex]\lambda[/itex] corresponds to [itex]n(n+1).[/itex]

I suppose [itex]P(x)=P_n(x)[/itex] for any [itex]n[/itex], but I'm not sure though. If this is the case, and you know this property, then integration by parts should do the trick.

- #5

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Thanks for help, I succeeded to do job.

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