Kleppner & Kolenkow find the tension of a rotating loop of string

AI Thread Summary
A high school student is seeking help with a physics problem from Kleppner and Kolenkow regarding the tension in a rotating loop of string. The student’s calculation yielded T = Mω^2/2π, while the book states T = (M*L*ω^2)/(2π)^2. Forum members pointed out that the student's final answer had incorrect dimensions for force, indicating an error in the calculation. The student acknowledged the oversight of not including a necessary factor, which helped clarify the solution. This exchange highlights the importance of dimensional analysis in verifying physics calculations.
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Hello, I am a high school student trying to learn physics out of Kleppner and Kolenkow. Unfortunately, the solutions to some of the problems are not available online, nor is a solutions manual available, so I am unable to find out where I am wrong in some cases, such as this one. I would appreciate your clarification.

Homework Statement


A piece of string of length L and mass M is fastened into a circular loop and set spinning about the center of a circle with uniform angular velocity ω. Find the tension in the string.

Homework Equations


The answer in the book states that T = (M*L*ω^2)/(2π)^2, whereas the answer that I got was T = Mω^2/2π.

The Attempt at a Solution


Please the attached pdf - I have tried to write as clearly as possible, and am unable to find how my solution is incorrect. Thank you!
 

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A useful check is whether the various items you have expressions for are dimensionally correct. Your final answer has dimensions MT-2, which is wrong for a force.
Apply the same test to your expression ΔθM/L.
 
haruspex said:
A useful check is whether the various items you have expressions for are dimensionally correct. Your final answer has dimensions MT-2, which is wrong for a force.
Apply the same test to your expression ΔθM/L.

Thank you! I forgot to include the factor R in there, which gets me where I want to go.
 
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