Knowing the Energy of a photon, what is the charge of a species?

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SUMMARY

The discussion centers on calculating the charge of a one-electron species when excited by a photon with an energy of 1.47E-17 J. The relevant equation used is E=-(2.18E-18)(Z²)/(N²). The participant initially calculated Z to be approximately 2.998, suggesting a charge of +3, but the correct charge of the ion is +2, as confirmed by the answer key. The confusion arose from misinterpreting the question, which asked for the charge of the ion rather than the nucleus.

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brbrett
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Homework Statement


An atom or ion with only one electron is excited from the ground state to the first excited state (n = 2) with a photon of 1.47E-17 J of energy. What is the charge on the one-electron species?
A. 0
B. +1
C. +2
D. +3
E. +4

Homework Equations


E=-(2.18E-18)(Z2)/(N2)

The Attempt at a Solution


I plugged in the information given into the equation:

(1.47E-17)=(-2.18E-18)(Z2)((1/4)-1)

With some algebra, I got Z=2.998, which may as well be a charge of +3.
However, according to the answer key, the correct answer is, in fact, +2 (C).
I would appreciate any guidance as to where I might be going wrong with this problem. :)
 
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What is the charge of the ion as a whole if the charge of the nucleus is 3?
 
Due to shielding, the effective charge would be about +2? I think I kinda see that maybe my calculations weren't wrong, but that I didn't understand the question right, but I still don't really get it.
 
You calculated Z, but Z is not what the question asks about. It asks you to calculate charge of the ion, not of the nucleus.
 
Ah, so then because I calculated the nucleus' charge to be +3, with a single electron there would be a charge of +2? That would make a lot of sense. Then I assume I didn't make any mistakes in solving for charge of the nucleus to figure out the ion's charge? Thanks!
 
Looks OK, although your first equation and the second equation are different.
 
Thanks!
 

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