What is the angle of static equilibrium for a ladder on ice?

AI Thread Summary
The discussion focuses on determining the tension in a rope supporting a foldable step ladder weighing 150 N, positioned at a 60° angle on ice. Participants emphasize the importance of showing work, such as free body diagrams (FBD), to receive assistance in solving the problem. There are challenges in equating torques around the ladder's pivots, with users noting a lack of progress in calculations. Clarification is sought regarding the ladder's configuration and the angle's application to each half. Effective problem-solving requires a clear demonstration of the steps taken and where difficulties arise.
engineerr
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Homework Statement
A foldable step ladder weighing 150 𝑁 is made of two halves connected by a pivot on top and
by a rope in the middle. The ladder is put on ice and its angle with the surface is 60°. What is
the tension of the rope?
Relevant Equations
net torque = zero
tried equating torques around the pivots of the ladder and equating them to zero but I'm not getting anywhere with that.
 
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engineerr said:
Homework Statement: A foldable step ladder weighing 150 𝑁 is made of two halves connected by a pivot on top and
by a rope in the middle. The ladder is put on ice and its angle with the surface is 60°. What is
the tension of the rope?
Relevant Equations: net torque = zero

tried equating torques around the pivots of the ladder and equating them to zero but I'm not getting anywhere with that.
Start with some diagrams (FBD). You aren't receive help until you show an honest effort has been made.
 
engineerr said:
tried equating torques around the pivots of the ladder and equating them to zero but I'm not getting anywhere with that.
We can't help you unless you show us what you did. Just mentioning it is not enough. We have to know where you got stuck or what you did wrong.
 
Welcome, @engineerr !

Could you clarify this part?
“The ladder is put on ice and its angle with the surface is 60°.”
Each half, I assume.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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