Lagrange multipliers and partial derivatives

phrygian
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Homework Statement



Find the point on 2x + 3y + z - 11 = 0 for which 4x^2 +y^2 +z^2 is a minimum

Homework Equations





The Attempt at a Solution



Using lagrange multipliers I find:

F = 4x^2 + y^2 + z^2 + l(2x + 3y + z)

Finding the partial derivatives I get the three equations:

df/dx = 8x + 2l
df/dy= 2y + 3l
df/dz= 2z + l

This is where I am stuck, what are the next steps for solving the system of equations?
 
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Well, first set them equal to 0! They are equivalent to x= -\lambda, 2y/3-\lambda and 2z= -\lambda. You can easily eliminate \lambda by setting those equal to each other. And don't forget that you have 2x+ 3y+ z= 11 as a third equation.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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