- #1
tshafer
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Homework Statement
We have a hoop of radius [tex]r[/tex] and mass [tex]m[/tex] resting on a cylinder of radius [tex]R[/tex] which rolls without slipping on the cylinder under the influence of gravity. If the hoop begins rolling from rest at the top of the cylinder, at what point does the hoop fall off of the cylinder?
Homework Equations
Hoop fixed on cylinder: [tex]f_1 = (R+r)-\xi = 0[/tex], [tex]\xi[/tex] is the distance from the center of the cylinder to center of the hoop.
Rolling w/out slipping: [tex]f_2 = Rd\theta - rd\phi = 0[/tex]
[tex]L = \frac 1 2 m \left( \dot{\xi}^2 + \xi^2\dot{\theta}^2 + r^2\dot{\phi}^2 \right) - mg\xi\cos\theta[/tex]
The Attempt at a Solution
[tex]\frac{d}{dt}\frac{\partial L}{\partial\dot{\xi}} - \frac{\partial L}{\partial\xi} \implies -m\xi\dot\theta^2+mg\cos\theta = -\lambda_1[/tex]
[tex]\frac{d}{dt}\frac{\partial L}{\partial\dot{\theta}} - \frac{\partial L}{\partial\theta} \implies m\xi^2\ddot{\theta}-mg\xi\sin\theta=R\lambda_2[/tex]
[tex]\frac{d}{dt}\frac{\partial L}{\partial\dot{\phi}} - \frac{\partial L}{\partial\phi} \implies mr^2\ddot\phi = -r\lambda_2[/tex]
I'm pretty sure the Lagrangian/E-L equations are wrong... I end up with a nonsensical expression for [tex]\lambda_2[/tex]. Am I thinking about the problem incorrectly?