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Lagrange's Undetermined Multipliers

  1. Sep 22, 2009 #1
    1. The problem statement, all variables and given/known data

    We have a hoop of radius [tex]r[/tex] and mass [tex]m[/tex] resting on a cylinder of radius [tex]R[/tex] which rolls without slipping on the cylinder under the influence of gravity. If the hoop begins rolling from rest at the top of the cylinder, at what point does the hoop fall off of the cylinder?


    2. Relevant equations

    Hoop fixed on cylinder: [tex]f_1 = (R+r)-\xi = 0[/tex], [tex]\xi[/tex] is the distance from the center of the cylinder to center of the hoop.
    Rolling w/out slipping: [tex]f_2 = Rd\theta - rd\phi = 0[/tex]

    [tex]L = \frac 1 2 m \left( \dot{\xi}^2 + \xi^2\dot{\theta}^2 + r^2\dot{\phi}^2 \right) - mg\xi\cos\theta[/tex]

    3. The attempt at a solution

    [tex]\frac{d}{dt}\frac{\partial L}{\partial\dot{\xi}} - \frac{\partial L}{\partial\xi} \implies -m\xi\dot\theta^2+mg\cos\theta = -\lambda_1[/tex]

    [tex]\frac{d}{dt}\frac{\partial L}{\partial\dot{\theta}} - \frac{\partial L}{\partial\theta} \implies m\xi^2\ddot{\theta}-mg\xi\sin\theta=R\lambda_2[/tex]

    [tex]\frac{d}{dt}\frac{\partial L}{\partial\dot{\phi}} - \frac{\partial L}{\partial\phi} \implies mr^2\ddot\phi = -r\lambda_2[/tex]

    I'm pretty sure the Lagrangian/E-L equations are wrong... I end up with a nonsensical expression for [tex]\lambda_2[/tex]. Am I thinking about the problem incorrectly?
     
  2. jcsd
  3. Sep 23, 2009 #2

    gabbagabbahey

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    Why are you only including the energy of the hoop? Is the cylinder fixed or is it free to rotate? Also, I assume the cylinder is resting on the ground?
     
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