Lagrangian and degrees of freedom

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Degrees of freedom for a particle in three-dimensional space is defined as three coordinates, while a rigid body has six due to its linear and rotational motion. The Lagrangian function, which depends on these coordinates and velocities, does not measure degrees of freedom but rather describes the dynamics of the system. In the Lagrangian formalism, a particle's degrees of freedom are treated separately for position and velocity, resulting in six degrees of freedom when considering both aspects. The discussion also touches on the relevance of the Lagrangian in quantum field theories and its connection to concepts in general relativity, although its utility in the latter is debated. Overall, the Lagrangian framework is essential for understanding complex physical theories like inflation and symmetry breaking in the universe.
shounakbhatta
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Hello,

I have a very basic question:

Degrees of freedom for a particle describes the formal state of a physical system. Like a particle in 3 dimension space has 3 co-ordinates and if it moves in 3 velocity components, then it has 6 degrees of freedom.

Lagrangian also measures this, right?
 
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Lagrangian measures nothing! It is a function which depends on s co-ordinates and s velocities (where s is degrees of freedom). And degrees of freedom for one particle moving in 3D space equals 3 (and not 6)!
 
You get 6 degrees of freedom for a _rigid body_: three for linear motion, and three for rotational motion.

Ideal particles don't have any size, so you cannot see them rotate!
 
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Degrees of freedom is just the number of independent quantities required to specify in a unique way the position of a particle or a system of particles.When you consider a particle 3 unique numbers are enough to specify its position assuming it is free to move in 3-D space. The number of Lagrange's equation that can be written down for a particle will be equal to the number of degrees of freedom for that particle.
 
I think I understand what shounakbhatta means. In the Lagrangian formalism, a particle has 6 degrees of freedom. It has 3 for the position and 3 for the velocity. When we specify the functional derivative of the Action to equal zero, we consider variations of the Lagrangian due to purely changes in the velocity and due to purely changes in the position. So the velocity and position of the particle are treated as separate degrees of freedom when we are varying the Lagrangian.
 
Thank you BruceW, I got it. Is Lagrangian in someway related to General Relativity or Quantum mechanics?
 
they absolutely love the Lagrangian in quantum field theories. I think there is a Lagrangian for General relativity. But I don't think it is very useful. Much more useful is when quantum field theory is introduced as part of our universe. This is how inflation and symmetry breaking e.t.c. are explained. Look up Andrei Linde "particle physics and inflationary cosmology", pretty interesting. It does assume some knowledge of quantum field theory and general relativity though. I am not able to understand all of it.
 
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