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I Lagrangian for a rolling disk on horizontal plane

  1. Nov 12, 2016 #1
    for a disck rolling on a horizontal plane the kinetic energy should be the kinetic energy of the CM of the disk with respect to the origin plus the kinetic energy due to the rotation of the disc about his CM
    so T= 1/2 (M V^2) +1/2(I ω^2)
    where M is the mass of the disk and V is the velocity of the CM and I is the moment of inertia of the disk and W is the angular velocity about the CM

    am i wrong ?
    why some books sole this problem for rotational kinetic energy only and ignore the term of kinetic energy that depends on the velocity of the center of mass with respect to the origin
    in ohter words they consider T = 1/2 I ω^2 only :(
     
  2. jcsd
  3. Nov 12, 2016 #2
    You would normally have to consider the translational motion also. In which books did you find this so that I can give a look at the problem.
     
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