How to apply Laplace transform on a non-homogeneous equation to find y

  • Thread starter Thread starter brandy
  • Start date Start date
  • Tags Tags
    Laplace
brandy
Messages
156
Reaction score
0

Homework Statement


do a laplace transform on a given non homogeneous equation.
to eventually find out y

Homework Equations


i don't think the equation is needed. however this non homogeneous equation is equal to Ae^kt


The Attempt at a Solution


well. i applied the laplace to the LHS. with all the '' and ' and stuff. but i didnt incorporate the RHS. can it just be equal to the Laplace of that side? I am thinking yes but not sure.
also, pretty baffled as to how that gives the original y.
 
Physics news on Phys.org
You'd need to apply the laplace of the RHS.

The LHS would have some function in s multiplied by Y(s).

so

f(s) Y(s) = A/(s-k) as the transform of Ae^kt is A/(s-k)

Y(s) = A/f(s)(s-k)

then you apply the inverse laplace transform on both sides. The LHS becomes y(t), the original y.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top