Laplace Transform: Answers for cos(4t-1)u(t-1) & cos4(t-1)u(t-1)

AI Thread Summary
The discussion focuses on finding the Laplace transforms for the functions cos(4t-1)u(t-1) and cos4(t-1)u(t-1). The Laplace transform of the first function is identified as e^-s/(s^2 + 16). For the second function, participants suggest using the identity for cos(A-B) to simplify the expression before applying the transform. There is a clarification that the second shift theorem is applicable, noting that the value of 'd' in both cases must be consistent. Overall, the conversation emphasizes the importance of showing effort before seeking assistance in solving these Laplace transform problems.
gsan
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what's the answer for laplace transform of the questions below?

1. cos(4t-1)u(t-1)
2. cos4(t-1)u(t-1)

I want to compare the difference between these two answer. Thanks!
 
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gsan, you've been told before that we can not help you until you first show us your effort.
 
Gokul43201 said:
gsan, you've been told before that we can not help you until you first show us your effort.

e^-s/(s^2 + 4^2) is the answer for i. or ii. ?
 
Your answer is the answer for question i. This is because when we refer to the second shift theorem in laplace transform, we can see that the value of 'd' must be the same. In this question, d = 1. Then from there, we can do the laplace transform. For the question ii, I myself not very sure.
Please correct me if I'm wrong. Thank you!
 
For part ii you need to use the idenity for cos(A-B)

cos(a - b) = cos(a)cos(b) + sin(a)sin(b)
 

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