Laplace Transform solution for 2nd order differential equation

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Discussion Overview

The discussion revolves around solving a second-order differential equation using the Laplace Transform method. Participants are focused on deriving the values of constants A, B, and C from the equations formed by applying initial conditions.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant expresses difficulty in deriving the values of A, B, and C from the attempted solution to the differential equation.
  • Another participant suggests that there are three simultaneous equations to solve for A, B, and C and mentions various methods such as elimination and Cramer's rule.
  • A participant acknowledges the help received and indicates they will try using Cramer's rule to solve the problem.
  • Concerns are raised about potential errors in the arithmetic related to the coefficients of A and C in the equations.
  • One participant realizes that the product of two negative numbers should be positive, indicating a correction in their understanding of the arithmetic involved.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correct values of A, B, and C, and there are indications of arithmetic errors that need clarification. The discussion remains unresolved regarding the final solution.

Contextual Notes

There are limitations in the clarity of the arithmetic steps taken to derive the coefficients, and the assumption made about s=0 is noted as potentially problematic.

khnbaba
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Homework Statement



d^2x/dt^2 - 3 dx/dt + 2x= 2e^3t

give that at t=0, x=5, and dx/dt=7

Homework Equations


i can't figure out how to derive the values of A, B, and C from the attempted equation solution. please help me out here. thanks


The Attempt at a Solution


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You've got three simultaneous equations in three unknowns, A, B, and C.

You can use elimination, Cramer's rule, guessing, whatever to solve for A, B, and C.

You've done good work up to this point. I'm surprised this point has stumped you.
 
thanks a lot steamKing you are being a big help, i went through cramer's rule examples and i think its going to solve my problem, i am going to try it now. plus i will learn some thing new :). i really appreciate your help. once again thanks
 
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SteamKing can you have a look to the final answer. thanks
 
For the second and third equations in your original system, for some reason you have the coefficients of A and C switched around.

Check your arithmetic in calculating the coefficients from the steps above that point, specifically where you let s = 0. Is the product of two negative numbers another negative number?
 
are you talking about equation 2, and eq 3 in the beginning?
and s=0 was just a supposition and the arithmetic below isn't part of the question which i realize now the product of two negative numbers should be positive not negative.
 
khnbaba said:
are you talking about equation 2, and eq 3 in the beginning?
and s=0 was just a supposition and the arithmetic below isn't part of the question which i realize now the product of two negative numbers should be positive not negative.

Yes. It appeared from your work that the calculations where s = 0 is where you started to calculate the coefficients of A, B, and C.
 
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thanks a lot for your time and efforts.
 

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