Largest Cylinder Volume in Cuboidal Log: What is the Maximum Possible Volume?

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The discussion centers on determining the volume of the largest cylinder that can be cut from a cuboidal log measuring 30 by 20 by 10 inches. The initial calculation suggested a radius of 5 inches and a height of 30 inches, resulting in a volume of 750π cubic inches, which contrasts with the book's answer of 1000π. Participants emphasize that maximizing the radius is crucial, but the height limitation of 10 inches restricts the cylinder's dimensions. The challenge lies in the inability to cut a full circle with a diameter of 20 inches due to the height constraint, leading to discussions about alternative shapes. Overall, the conversation highlights the importance of correctly visualizing and calculating the cylinder's dimensions within the given constraints.
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Homework Statement


What is the volume of the largest cylinder that can be cut out of a cuboidal log of
wood of dimensions 30*20*10 inches?

Homework Equations


volume of cuboid = length*breadth*height
volume of cylinder= *[radius]²*height


The Attempt at a Solution



Radius of largest cylinder=5 inches
height of largest cylinder=30 inches
volume of largest cylinder=750 inch³
But book answer is 1000.
 
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Hi Amith2006! :smile:
Amith2006 said:
volume of cylinder= *[radius]²*height

Yes, the radius is squared but the height is on its own.

So don't you you want the radius to be as large as possible?

ooh … got to go now … Doctor Who starting on telly! :biggrin:
 
tiny-tim said:
Hi Amith2006! :smile:


Yes, the radius is squared but the height is on its own.

So don't you you want the radius to be as large as possible?

ooh  got to go now  Doctor Who starting on telly! :biggrin:


so doed it seem ok?
 
Amith2006 said:
so does it seem ok?

No!

You want the radius to be as large as possible,

but you've made it the smallest possible (5).

Try again, and see the difference! :smile:
 
tiny-tim said:
You want the radius to be as large as possible,

but you've made it the smallest possible (5).

:smile:

The problem that i face is that i can't cut out a circle of diameter 20 inches because the height is only 10 inches. i can only do so by making the Cross Section oval.
 
Amith2006 said:
The problem that i face is that i can't cut out a circle of diameter 20 inches because the height is only 10 inches. i can only do so by making the Cross Section oval.

No … draw a diagram … 6 bricks in two layers of 3.

One side is 2 bricks x 3 bricks.

Draw the circle on that side! :smile:

(btw, what happened to π in the formula?)
 

thanx.
 
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