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dolerka
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Homework Statement
Steam at 100°C is injected into 1.8 kg of water at 22°C in a well-insulated container, where it condenses and mixes with the existing water, reaching thermal equilibrium. If the final temperature of the well-mixed water is 25°C, what is the mass of the injected steam?
Latent heat of vaporization of water, Lv=2.26e6
Homework Equations
Q = cmΔT, equation for specific heat. specific heat constant c=4178
Q=Lvm, equation for energy of vaporization, m=mass.
The Attempt at a Solution
I first stated that since the the steam is losing energy during its phase change it is negative, -Qp.-Qp=Lvms
The amount of energy for the temperature change of the steam.
Qs=cmsdTs
Qs=(4178)ms(22-100)
The amount of energy for the temperature change of the water.
Qw=cmwdTw
Qw=(4178)(1.8)(25-22)
I know i need arrange together in someway but I am just a little confused on that part.