- #1
heelp
- 23
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what mass of steam at 100 c must be added to 1.ookg of ice to yeild liquid water 20c ?
this is what I have so for c*m* displacement of temperature =m *L
this is what I have so for c*m* displacement of temperature =m *L
The formula for calculating the mass of steam needed for 1kg of ice to yield 20°C water is:
ms = mi x (Lf + Cp x (Tf - Ti)) / (hfg x (Tf - Ti))
where:
ms = mass of steam (kg)
mi = mass of ice (kg)
Lf = latent heat of fusion for water (334 kJ/kg)
Cp = specific heat capacity of water (4.186 kJ/kg·K)
Tf = final temperature (20°C)
Ti = initial temperature (-10°C)
hfg = specific enthalpy of vaporization for water (2257 kJ/kg)
The calculation assumes that the ice is initially at a temperature of -10°C and the steam is at a temperature of 100°C, and that the process is occurring at standard atmospheric pressure.
The purpose of this calculation is to determine the amount of energy (in the form of steam) needed to melt a given amount of ice and raise the resulting water to a desired temperature.
The accuracy of the calculated mass of steam can be affected by variations in the properties of water (such as specific heat capacity and latent heat of fusion), as well as changes in atmospheric pressure and temperature.
The calculated mass of steam can be used in practical applications such as determining the energy requirements for melting ice in industrial processes, designing heating and cooling systems, and understanding the thermodynamics of phase changes in water.