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a projectile of mass 250g travelling at 1200m/s impacts and sticks to a stationary 3500g object.

What will be the resulting velocity of the two combined objects....

Many thanks

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- Thread starter pdaniels77
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a projectile of mass 250g travelling at 1200m/s impacts and sticks to a stationary 3500g object.

What will be the resulting velocity of the two combined objects....

Many thanks

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arildno

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What must it be just AFTER the collision?

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I am hoping that the resulting velocity will be in the region of 120m/s.

Regarding the momentum...the 3500g body is stationary and impact from the 250g body is in a straight line....think of 2 balls....with the smaller one impacting the larger one dead centre

- #4

arildno

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The total of which equals the momentum the 250g body has on its own; agreed?

That quantity must be conserved after collision, for the composite body with mass 3500+250 g

If you do this correctly, since 3500=14*250, the new velocity will be 1/15 of the impact velocity just prior to the colision (80 m/s).

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arildno

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[tex]\frac{1}{1+\frac{m_{s}}{m_{b}}}v_{0}=120[/tex]

Thus, you have two parameters you can play about with independently, the mass ratio and the initial velocity. You have infinitely many solutions to your problem. Pick the one you like best.

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brilliant thank you

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arildno

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But, you have YET more energy to account for!

In this type of inelastic collision, kinetic energy of the system of two bodies has become TRANSFERRED to other types of energy, such as to sound, heat, and the amount of energy needed to create permanent deformations in either, or both objects.

THAT amount of energy is simply the difference in the whole system's energy after the collision to the whole system's total kinetic energy before the collision.

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Hi SORRY TO BOTHER YOU AGAIN BUT U HAVE JUST BEEN PLAYING AROUND WIT THE FORUMLAE

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arildno

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I told you the answer with your figures was 80 m/s. Right in post 4.

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