Lebesgue Integral: Practice Problem

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Homework Statement


Suppose that f is a nonnegative Lebesgue measurable function and E is a measurable set.
Let A = {x ∈ E : f(x) = ∞}. Show that if ##\int_E f dλ < ∞## then ##λ(A) = 0##

Homework Equations

The Attempt at a Solution


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Let ##\phi(x)=\sum_{x\in A}a_i\mathcal{X}_{A_i}(x)## so by the construction of ##A##, ##a_i=\infty## for all ##i## and ##A=\cup A_i##
Then
##\infty\ge\int_E f dλ= \int_{E-A}f dλ+\int_Af dλ=\int_{E-A}f dλ+\int \phi(x)=\int_{E-A}f dλ+\sum a_i \lambda(A_i)##
##\implies \lambda(A_i)=0 ## for all i
##\implies \lambda(A)=0##
This seems simple and intuitive so I'm worried I'm missing something.
 
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No, that's pretty much the idea.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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