Leg Presses Work Energy Theorem Confusion

AI Thread Summary
The discussion centers on a physics problem involving leg presses and the work-energy theorem. The user is confused about calculating the work done when compressing two springs, initially assuming the total work equals the sum of the work done on each spring. Clarification is provided that the effective spring constant can be represented as a single value for both springs, allowing for a simplified calculation. Both methods of calculation should yield the same results for the required force and additional work. Understanding the effective spring constant is key to resolving the confusion.
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Homework Statement



As part of your daily workout, you lie on
your back and push with your feet against a platform attached to
two stiff springs arranged side by side so that they are parallel to
each other. When you push the platform, you compress the springs.
You do 80.0 J of work when you compress the springs 0.200 m
from their uncompressed length. (a) What magnitude of force must
you apply to hold the platform in this position? (b) How much
additional work must you do to move the platform 0.200 m
farther, and what maximum force must you apply?

Homework Equations



Work Energy theorem ONLY!

The Attempt at a Solution


I assumed that the 80 J would be equal to the sum of work done to compress each spring... So 80 J = 2* (.5 K x^2) ... However, the book had an attempt directly the 80 J = .5 Kx^2... Kindly Clarify why is it so if the force is applied on two springs? THANKS A LOT!
 
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Perhaps they are letting K represent the effective spring constant of both springs together. Your approach is also fine. Both methods should give the same answers for (a) and (b).
 
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