Solve for di: Negative Effect on Object Distance?

  • Thread starter Thread starter Grekory
  • Start date Start date
  • Tags Tags
    Lenses
AI Thread Summary
To solve for the image distance (di) using the formula -di/do = hi/ho, first cross-multiply or multiply both sides by -do. Given the values ho = 3cm, hi = 4cm, and do = 5cm, the calculation leads to di = -6.67cm, indicating the image is inverted. The negative sign in the result signifies that the image formed is real and inverted. Understanding that negative di values correspond to real images clarifies the confusion around the negative aspect of the formula.
Grekory
Messages
2
Reaction score
0
When I'm given do, ho, and hi. How would i solve for di
Normally i would do -di/do = hi/ho and cross-multiply but I'm not sure how the negative comes into effect.

do = object distance
di = image distance
ho = object height
hi = image height



If...

ho = 3cm
hi = 4cm
do = 5cm

What would be di?

Thanks
 
Physics news on Phys.org
Please provide the complete statement of the problem you are trying to solve. (I presume that a negative image height means that the image is inverted.)
 
It's just made up values and i want to know how i would solve for di. The negative in the formula confuses me
 
Start with:
-di/do = hi/ho

You can solve for di by cross-multiplying if you like, or just multiply both sides by -do. As I said before, a negative value for di just means that the image is inverted. (Real images are inverted.)
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Thread 'A bead-mass oscillatory system problem'
I can't figure out how to find the velocity of the particle at 37 degrees. Basically the bead moves with velocity towards right let's call it v1. The particle moves with some velocity v2. In frame of the bead, the particle is performing circular motion. So v of particle wrt bead would be perpendicular to the string. But how would I find the velocity of particle in ground frame? I tried using vectors to figure it out and the angle is coming out to be extremely long. One equation is by work...
Back
Top