Let's think crack u'r brain with this qn.

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The discussion clarifies that Earth's gravitational pull extends infinitely, but its strength diminishes with distance, decreasing by the square of the distance from the Earth's center. A comet, initially at rest and 2.7 billion light-years away, would experience an extremely weak gravitational acceleration of approximately 6 x 10^-42 m/s². As the comet approaches Earth, its acceleration increases, ultimately reaching about 10 m/s² as it nears the surface. By the time the comet impacts Earth, it would be traveling at approximately 11 km/s. This illustrates the gradual increase in speed due to gravitational attraction over vast distances.
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ok...

note: Earth's pull of gravity starts 2.7 billion light years away.<Got this info from somewhere else>(may not be true, u are free to use u'r own)

A comet which is floating freely in space, suddenly, got attracted by Earth's gravity and started accelerating at 10m/s-2 towards earth...What would be the speed juz before it touches Earth's soil?
 
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First off, the Earth's gravity pull does not "start" at any given distance from the Earth, it reaches to inifinty.

Secondly it does not maintain full surface strength at all distances, it falls off in strength by the square of the distance you are from the center of the Earth. IOW, if you moved twice as far from the center of the Earth as you are now sitting on the surface, the acceleration due to gravity would drop to 1/4 that of the surface, or to 2.5/m/sec^2.

At 2.7 billion lightyears away, said comet would start to accelerate at about 6*10^-42 meters/sec^2, our in other words, you could watch it for a very long time without even noticing that it was moving.

As it slowly got closer to the Earth, it acceleration would increase. By the tim it struck the Earth it would be moving at about 11 km/sec. (Assuming it started at reast with respect to the Earth.)
 
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