Silversonic
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I can't wrap my head around this proof that the sum of two nilpotent ideals is nilpotent, I get stuck at one stage:
http://imageshack.com/a/img706/5732/5wgq.png
I'm fine with every except showing by induction (I+J)^{N+k} = I^k \cap J + I \cap J^k. Here's my attempt;
Base case: k = 1,
(I+J)^{N+1} = [I+J, (I+J)^N] \subseteq [I+J,I \cap J] = [I, I \cap J] + [J, I \cap J] \subseteq I \cap J + I \cap J
since [I, I \cap J], [J, I \cap J] \subseteq I \cap J as I \cap J is an ideal.
Now inductive step;
(I+J)^{N+k+1} = [I+J, (I+J)^{N+k}] = [I+J, I^k \cap J + I \cap J^k] = [I, I^k \cap J] + [J, I^k \cap J] + [I,I \cap J^k] + [J,I \cap J^k]
Now it's easy to see
[I, I^k \cap J] \subseteq I^{k+1} \cap J
[J, I \cap J^k] \subseteq I \cap J^{k+1}
But I have no idea what I can do with the [J, I^k \cap J] + [I,I \cap J^k] term so that it reduces to the form I want. Any help?
http://imageshack.com/a/img706/5732/5wgq.png
I'm fine with every except showing by induction (I+J)^{N+k} = I^k \cap J + I \cap J^k. Here's my attempt;
Base case: k = 1,
(I+J)^{N+1} = [I+J, (I+J)^N] \subseteq [I+J,I \cap J] = [I, I \cap J] + [J, I \cap J] \subseteq I \cap J + I \cap J
since [I, I \cap J], [J, I \cap J] \subseteq I \cap J as I \cap J is an ideal.
Now inductive step;
(I+J)^{N+k+1} = [I+J, (I+J)^{N+k}] = [I+J, I^k \cap J + I \cap J^k] = [I, I^k \cap J] + [J, I^k \cap J] + [I,I \cap J^k] + [J,I \cap J^k]
Now it's easy to see
[I, I^k \cap J] \subseteq I^{k+1} \cap J
[J, I \cap J^k] \subseteq I \cap J^{k+1}
But I have no idea what I can do with the [J, I^k \cap J] + [I,I \cap J^k] term so that it reduces to the form I want. Any help?
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