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Homework Help: Light bulb(electric current)

  1. Apr 2, 2013 #1
    1. The problem statement, all variables and given/known data
    What is the maximum number of 60.0 W light bulbs that can be put in a household circuit (V= 110V) without tripping the circuit breaker if the maximum current through the circuit is 20.0 A?

    2. Relevant equations

    P= Vi

    3. The attempt at a solution

    P= VI => I=P/V for each light bulb's current...I= 60/110v = 0.545454A for 1 light bulb.

    Max 20.0A so 20/0.545454 = 36.66666666 => 36 light bulbs you can put max.

    Please check see if i got it right.
  2. jcsd
  3. Apr 2, 2013 #2


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    Homework Helper

    The logic is good. In practice you may be in trouble since a 60 W light globe briefly operates at more than 60W when it is first turned on, so if you switched them all on at once the fuse may trip.
  4. Apr 2, 2013 #3
    ahh thank you. This is for an assignment so we are not actually going to do that in real life. Just wondering if my calculations are right!
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