Limit and diffirentiability of a function

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The discussion focuses on proving the differentiability of the function |f + tg|^p for complex numbers f and g, specifically for 1 < p < ∞. The limit expression provided indicates that the function is differentiable, and the user attempts to manipulate the convex function |x|^p to demonstrate this. Despite several attempts, including the application of L'Hôpital's rule, the user finds they are consistently off by a factor of p/2. The rewriting of the function as |f + tg|^2 helps in the analysis but does not lead to the desired conclusion. The conversation highlights the challenges in proving differentiability in this context.
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Homework Statement


For complex numbers f and g, and for 1&lt;p&lt;\infty we have \lim_{t\rightarrow 0}\dfrac{|f+tg|^p-|f|^p}{t}=|f|^{p-2}(\bar{f}g+f\bar{g}); i.e., |f+tg|^p is differentiable.

I would like to show that the above statement is true.


Homework Equations





The Attempt at a Solution



I have try several attempts in the direction of manipulating the convex function |x|^p. But no reasonable conclusions yet.
 
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So, I have made some progress by rewriting the problem and using L'hopitals rule. But I am still off by a factor of \dfrac{p}{2}.

rewriting: |f+tg|^2=f\bar{f}+tf\bar{g}+t\bar{f}g+t^2g\bar{g}

When I apply L'Hopitals rule I get \dfrac{p}{2}|f|^{p-2}(\bar{f}g+f\bar{g})
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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