Can L'hopital's Rule be Applied to this Limit?

In summary, the given limit problem is \lim_{x \rightarrow {\infty}} \left(\frac{1 \, + \, tan\left(\frac{\pi}{2x}\right)}{1 \, + \, sin \left(\frac{\pi}{3x}\right)} \right)^{x}. To solve it, we can let y = the limit, take ln of both sides, and use L'hopital's rule by plugging in the limit to get \frac{0}{0}.
  • #1
hadi amiri 4
98
1
[tex]\lim_{x \rightarrow infinity}/ left(\frac{\1+Tan\frac{/pi}{2x}}{1+sin\frac{/pi}{3x}}}right)^x[/tex]
 
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  • #2


sorry i made mistake in typing
 
  • #3


So what does the limit problem actually look like?
 
  • #4


hadi amiri 4 said:
[tex]\lim_{x \rightarrow infinity}/ left(\frac{\1+Tan\frac{/pi}{2x}}{1+sin\frac{/pi}{3x}}}right)^x[/tex]

I assume you meant

[tex] \lim_{x \rightarrow {\infty}} \left(\frac{1 \, + \, tan\left(\frac{\pi}{2x}\right)}{1 \, + \, sin \left(\frac{\pi}{3x}\right)} \right)^{x} [/tex]

then I would suggest letting that = y, then take ln of both sides and you should get something like:

[tex] ln(y) \, = \, \lim_{x \rightarrow {\infty}} \frac{ln\left(\frac{1 \, + \, tan\left(\frac{\pi}{2x}\right)}{1 \, + \, sin \left(\frac{\pi}{3x}\right)} \right)}{\frac{1}{x}} [/tex]

which if you "plug in" the limit should give you [tex]\frac{0}{0}[/tex] making it a candidate for L'hopital. Try that.
 

1. What is the limit candidate for L'hopital?

The limit candidate for L'hopital is a mathematical rule used to evaluate the limit of an indeterminate form, such as 0/0 or ∞/∞. It states that if the limit of a function f(x) and g(x) both approach 0 or ∞ as x approaches a particular value, then the limit of the ratio of f(x) and g(x) is equal to the limit of the ratio of their derivatives.

2. When can L'hopital's rule be applied?

L'hopital's rule can be applied when the limit of a function f(x) and g(x) both approach 0 or ∞ as x approaches a particular value. It is also applicable when the limit of the ratio of f(x) and g(x) is in an indeterminate form such as 0/0 or ∞/∞.

3. How do you use L'hopital's rule to evaluate limits?

To use L'hopital's rule to evaluate limits, identify the indeterminate form of the limit, then take the derivative of both the numerator and denominator of the function. This will give you a new function that has a simpler form. If the limit of the new function still approaches an indeterminate form, you can repeat the process until the limit can be evaluated.

4. Are there any limitations to L'hopital's rule?

Yes, there are limitations to L'hopital's rule. It can only be applied to limits in which both the numerator and denominator approach 0 or ∞. It also cannot be used if the limit has a different indeterminate form such as 1^∞ or ∞^0. Additionally, L'hopital's rule cannot be used if the limit is not continuous.

5. What are some real-world applications of L'hopital's rule?

L'hopital's rule has many real-world applications in fields such as physics, engineering, and economics. It can be used to calculate the rate of change of a function, find the maximum or minimum value of a function, and solve optimization problems. It is also used in calculating the derivatives of complex functions in order to describe the behavior of systems in the real world.

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