1. The problem statement, all variables and given/known data Limit as p->infinity of ((p^2-p+1)/((P+1)^2)^(2p+3) In case the parenthesis are confusing, its one giant fraction all raised to the (2p+3) power. 2. The attempt at a solution I set the entire problem equal to L and took the ln of both sides. This lets me move the power down using a log rule So: ln(L) = lim p->infinity (2p+3)* ln((p^2-p+1)/((P+1)^2) Using the log rule of ln(m/n) = ln(m) – ln(n): lim p-> infinity (2p+3)[ln(p^2-p+1) - 2ln(p+1)] At this point Im not sure. I think I can put it into a form where I can then use hopital's rule? So: [ln(p^2-p+1) - 2ln(p+1)] / (1/(2p+3)) Will that help? I took the derivative of top and bottom but its not looking like something I can use.