Limit of Summation: Find Solution

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SUMMARY

The limit of the summation as n approaches infinity for the expression (1/n) * ((i/n)^2) converges to 1/3. The correct approach involves recognizing that the summation can be factored into (1/n^3) * Σ(i^2) from i=1 to n. Utilizing the formula for the sum of the first n squares, Σ(i^2) = n(n+1)(2n+1)/6, leads to the conclusion that the limit evaluates to 1/3 as n approaches infinity.

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Homework Statement



Find the limit n to Infinity of summation (i=1 to n) 1/n * ((i/n)^2)


The Attempt at a Solution



I thought it was zero at first because 1/n goes to zero but apparently that's not right. I also tried to convert to an integral and got integral of i^2/n^2 which equals i^3/3*n^2 but that's not right either.
 
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Kurani said:

Homework Statement



Find the limit n to Infinity of summation (i=1 to n) 1/n * ((i/n)^2)


The Attempt at a Solution



I thought it was zero at first because 1/n goes to zero but apparently that's not right. I also tried to convert to an integral and got integral of i^2/n^2 which equals i^3/3*n^2 but that's not right either.

Assuming you have typed what you meant to type, you can factor out the n's:

[tex]\sum_{i=1}^n \frac 1 n \frac {i^2}{n^2} = \frac 1 {n^3}\sum_{i=1}^n i^2[/tex]

Do you know the formula for the sum of the first n squares? Put that in and see what happens as n → ∞.
 
Yeah, I realized I had to do that right after I posted, it comes out to 1/3. Thanks
 

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