Limit question. Have solution, need to know how to get it.

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Homework Statement



I was working on a problem in my book, and I didn't know how to answer the question. So I looked at the solution manual. and it had this

http://imgur.com/VF4yl

I do not know where the (cosx + 1) on the bottom came from. Any ideas? Please explain.

Homework Equations



sin(x+y)= sinx cosy + cosx siny

The Attempt at a Solution



I get the top part though, you factor out the 2, multiply the cos and sin then it becomes sin(x+y) sort of thing.Ok, nevermind, I am sorry, I didn't realize they factored out the cosx-1 and then multiplied by (cosx +1)/(cosx+1) So I got it now.
 
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bored2death97 said:

Homework Statement



I was working on a problem in my book, and I didn't know how to answer the question. So I looked at the solution manual. and it had this

http://imgur.com/VF4yl

I do not know where the (cos-1) on the bottom came from. Any ideas? Please explain.
They multiplied by 1 in the form
$$ \frac{cos(x) + 1}{cos(x) + 1}$$
bored2death97 said:

Homework Equations



sin(x+y)= sinx cosy + cosx siny
One that is relevant to the question you asked is:
sin2(x) + cos2(x) = 1
bored2death97 said:

The Attempt at a Solution



I get the top part though, you factor out the 2, multiply the cos and sin then it becomes sin(x+y) sort of thing.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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