1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Limits and Disc.

  1. Apr 23, 2010 #1
    1. f(x)= 3x2-12x / x2-6x +8

    f(x) can be made continuous at x =4 by defining f(4)=6

    I know that the removable disc. is at x=2 and the non removable is at x=4. So there is an asymptote at x=4. How is it possible to define it there?
  2. jcsd
  3. Apr 23, 2010 #2


    User Avatar
    Science Advisor
    Homework Helper

    You have that backwards. There's no asymptote at x=4. There's an asymptote at x=2. Find the limit as x->4. Show your work this time.
  4. Apr 23, 2010 #3
    Ugh! Thanks I am just a fool and factored incorrectly. Final exams =(. Thank you !

    3x(x-4) / (x-4)(x-2) = f(x)
    So the lim as x-->4 f(x)=6
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook