Limits of functions with negative exponents

AI Thread Summary
The limit of the function as h approaches 0 is expressed as lim h->0 [(11+h)^-1 - 11^-1]/h. The initial attempt involved combining fractions in the numerator, leading to a result of 121 when substituting h with 0. However, a sign error was identified in the calculations, indicating that the solution needs to be re-evaluated. Correcting the sign error is essential for accurately determining the limit. Proper resolution of the limit will clarify the behavior of the function near the point of interest.
alexk307
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Homework Statement



lim h->0 [(11+h)^-1 - 11^-1]/h

Homework Equations





The Attempt at a Solution



I made the numerator into two fractions with the denominator h. After combining the fractions in the numerator I was left with 121 when I put in 0 for h.
 
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alexk307 said:

Homework Statement



lim h->0 [(11+h)^-1 - 11^-1]/h

Homework Equations





The Attempt at a Solution



I made the numerator into two fractions with the denominator h. After combining the fractions in the numerator I was left with 121 when I put in 0 for h.

You have a sign error. Check your work.
 

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