Limits of Sequences Homework: Proving Limit of a_n/n = 0

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Homework Statement



For a sequence a_n:

If lim (a_n) =2, use the definition of a limit to show that lim (a_n / n) = 0

all limits are as n goes to infinity

The Attempt at a Solution



I know that I need to show:

Give any \epsilon>0 there is some M so that

if n>M then |a_n / n| < \epsilonBut I can't Figure out how to do that.

Any help would be much appreciated! I have an exam in a few days and I came across this as a practice problem.

-NN
 
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by the way: I totally understand intuitively why this is the case, I just figure out how to express it formally.

I know that as n approaches infinity, the fraction approaches (a fixed number)/(infinity) , which means it approaches 0. How can I write this using the formal definition?
 
You know the limit of an, so you know there exists an N such that for n>N, |an-2|<ε.

Can you tweak that to get something that'll bound |an/n| from above? Or maybe use the triangle inequality?
 
I have tried using the triangle inequality to do so, but i haven't figured anything out yet.
 
NickMusicMan said:
I have tried using the triangle inequality to do so, but i haven't figured anything out yet.

Pick a value of epsilon. Then just divide the formal definition of limit by n.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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