Limits of the Path Length of B-field induced gyroradius

AI Thread Summary
The discussion centers on deriving the path length of a charged particle in a magnetic field (B-field) using equations for helical motion and gyroradius. The participant calculates the path length as P = √((v_perp*m^*/(qB))^2 + L^2) but encounters issues with boundary conditions, particularly at zero and infinite magnetic fields. At zero field, the expected path length should equal L, but the derived expression becomes infinite, raising questions about the applicability of gyroradius in this scenario. The participant seeks clarification on the limiting behavior of the path length as the magnetic field approaches these extremes. The problem highlights the complexities of modeling particle motion in varying magnetic field conditions.
thefireman
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Hi,
I am trying to derive the path length of a charged particle in a B-field. I am assuming the particle will travel a distance L along the applied field. Using the following equations for the path length of a helix and gyroradius:
Helix defined as
[a*cos(t),a*cos(t),b*t]for t on [0,T] has a path length of
P=\sqrt{(a^2+b^2)}
r=\frac{v_{perp}m^*}{qB}
and assuming that bt must equal L at T=1 (parametrize helix from 0 to 1), I get the following expression:

P=\sqrt{(\frac{v_{perp}m^*}{qB})^2+L^2}

However, the bounds do not make sense. At zero field, It should simply travel in a straight line, i.e. P=L.
I am not sure about the "infinite" field, since it is oscillating more rapidly but with an ever decreasing radius. I could argue that the radius being 0 means only the vertical distance is traveled, or that it just rotates infinity at 0 radius?
In either case, I cannot get the BC for B=0, as this causes the expression to be infinite.

Can I simply not apply the gyroradius in a zero field condition, or did I derive this incorrectly? What is the limiting case of infinite field? Actually quite an interesting problem!
 
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