Limits of Trigonometric Functions.

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gabyoh23
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Limits of Trigonometric Functions. URGENT!

Homework Statement


Evaluate stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [sin(\frac{2e}{x3}) \bullet (arctanx)]


Homework Equations


All I know is that the equation stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [tex]\frac{sin x}{x}[/tex] = 1 might be helpful, but I'm not sure how to apply it to this particular problem.


The Attempt at a Solution


I talked to a friend of mine who's in Calc III, and she said that the whole limit would be equal to 0 since arctan(0) = 0, and sin[tex]\frac{2e}{x<sup>3</sup>}[/tex] is undefined, and the zero beats out the undefined value. This might be right, but how would I show that mathematically?

All help is greatly appreciated as I'm kind of in a crunch here :)
 
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gabyoh23 said:

Homework Statement


Evaluate stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [sin(\frac{2e}{x3}) \bullet (arctanx)]


Homework Equations


All I know is that the equation stackrel{lim}{x [tex]\rightarrow[/tex]0}[/tex] [tex]\frac{sin x}{x}[/tex] = 1 might be helpful, but I'm not sure how to apply it to this particular problem.


The Attempt at a Solution


I talked to a friend of mine who's in Calc III, and she said that the whole limit would be equal to 0 since arctan(0) = 0, and sin[tex]\frac{2e}{x<sup>3</sup>}[/tex] is undefined, and the zero beats out the undefined value. This might be right, but how would I show that mathematically?

All help is greatly appreciated as I'm kind of in a crunch here :)
Here's your corrected limit expression.

Evaluate [tex]lim_{x \rightarrow 0} sin(\frac{2e}{x^3}) arctanx[/tex]

Your friend is leading you astray. It's not necessarily true that an expression tending to zero "beats out" an undefined value. What is true is that -1 <= sin(u) <= 1 for all real values of u.
 


Thanks for correcting my formatting. I was in a rush, and I accidentally hit the "submit post" button before previewing it.

Thanks for the input!