Limits of x/ln(x): Solving Confusion

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Homework Statement


Hello all,

I am having hard time with limits.

1. limx->1- x/ln(x)

2. limx->1+ x/ln(x)

Homework Equations

The Attempt at a Solution


1. limx->1- x/ln(x)
= 1-/ln(1-)
ln(1-) = 0-

I seriously don't understand why ln(1-) = 0-

2. limx->1+ x/ln(x)
= 1+/ln(1+)
ln(1+) = 0+

I seriously don't understand why ln(1+) = 0+thanks
 
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Do you know what the natural logarithm graph looks like?
 
axmls said:
Do you know what the natural logarithm graph looks like?
yes I do, doing limits with a graph is easy, I have to resolve this by doing algebra.
 
You say you don't understand why ln(1) = 0. This is common knowledge about the logarithmic function. You have a function approaching 0 in the denominator and a function approaching 1 in the numerator. What does that tell you?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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