Limits Question: Proving Sn <= b for Finite n

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Hello,
I'm having trouble with this question.
Let Sn be a sequence that converges. Show that if Sn <= b for all but finitely many n, then lim sn <= b.
This is what I'm trying to do, assume s = lim Sn and s > b. (Proof by contradiction) abs(Sn-s) < E, E > 0. Don't know what to do from there, but maybe set E = s -b. E is epsilon by the way. Probably to start using latex...

If anyone could help, that would be awesome.
 
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Your idea is fine so far. Now what does |s_n - s| &lt; \epsilon = s-b for all n > N imply?
 
s is a upper bound, so the Sn-s is negative. So abs(Sn-s) < s -b doesn't hold true all n. I'm not sure though
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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