Limits with three variables (a different problem)

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SUMMARY

The limit of the function (x^2 + y^2)ln(x^2 + y^2) as (x,y) approaches (0,0) can be evaluated using polar coordinates. By substituting x and y with r*cos(θ) and r*sin(θ), the limit simplifies to r^2 * ln(r^2) as r approaches 0 from the right. The final conclusion is that this limit equals 0, confirming that evaluating the limit from one direction is sufficient due to the non-negative nature of r.

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Homework Statement



the limit as (x,y)->0,0 of (x^2+y^2)ln(x^2+y^2)
(Hint: as (x,y)->(0,0) r->0(from the right)

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The Attempt at a Solution



I converted to polar coordinates then used trig identities and eventually got to the limit of r->0(from theright) of r^2 * (ln(r^2)) I eventually got this limit to equal 0. I'm pretty sure to make sure the limit exists I have to evaluate it as r->0 (from the left) as well but I'm not sure how...
 
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You only need to evaluate the limit of r from one direction, as r is a variable that is always non-negative. Remember it represents a radius, ie a positive number.
 
ohhhh I see thanks
 

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