the limit as (x,y)->0,0 of (x^2+y^2)ln(x^2+y^2)
(Hint: as (x,y)->(0,0) r->0(from the right)
The Attempt at a Solution
I converted to polar coordinates then used trig identities and eventually got to the limit of r->0(from theright) of r^2 * (ln(r^2)) I eventually got this limit to equal 0. I'm pretty sure to make sure the limit exists I have to evaluate it as r->0 (from the left) as well but I'm not sure how...