Line integral and greens theorem

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Homework Statement


\int \vec{F} \cdot d\vec{r} where F=<y,0> and \vec{r}=unit circle.


Homework Equations


i'd prefer to do this one without greens theorem (using it is very easy).


The Attempt at a Solution


y=r\sin\theta and x=r\cos\theta. now \int \vec{F} \cdot d\vec{r}=\int r\cos\theta (\cos\theta dr -r\sin\theta d\theta) where \theta [0,\pi] and r [0,1]
but what do i do with my bounds of this single integral? please help! (i used the chain rule with the above substitutions to evaluate \int \vec{F_x}dx since the dy component seems to be zero)

thanks!
 
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joshmccraney said:

Homework Statement


\int \vec{F} \cdot d\vec{r} where F=<y,0> and \vec{r}=unit circle.


Homework Equations


i'd prefer to do this one without greens theorem (using it is very easy).


The Attempt at a Solution


y=r\sin\theta and x=r\cos\theta. now \int \vec{F} \cdot d\vec{r}=\int r\cos\theta (\cos\theta dr -r\sin\theta d\theta) where \theta [0,\pi] and r [0,1]
but what do i do with my bounds of this single integral? please help! (i used the chain rule with the above substitutions to evaluate \int \vec{F_x}dx since the dy component seems to be zero)

thanks!

##r=1## on the circumference of the unit circle. You parameterization should be$$
\vec r(t)=\langle \cos t, \sin t \rangle,~~\vec F = \langle \sin t , 0\rangle$$
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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