Line integral over a Vector Field

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
9 replies · 3K views
Smazmbazm
Messages
45
Reaction score
0

Homework Statement



Given a vector field

[itex]F(x,y,z) = (yz + 3x^{2})\hat{i} + xz\hat{j} + xy\hat{k}[/itex]

Calculate the line integral

[itex]∫_{A}^{B}F\bullet dl[/itex]

where A = (0,1,3) and B = (1,2,2)

Homework Equations



Right, first of all, what is dl ? I've gone over all my course notes and don't see dl anywhere. I managed to find on this site that dl = (dx, dy, dz). Is that the case?

If so, my attempt at the solution is

[itex]∫_{A}^{B}(yz + 3x^{2})dx + xzdy + xydz[/itex]

Now what? I'm not really sure how to set the intervals from those 2 points in space. Am I supposed to do something like

[itex]∫_{0}^{1}(yz + 3x^{2})dx + ∫_{1}^{2}xzdx +∫_{3}^{2}xydz[/itex] ?

Thanks for any assistance.
 
Physics news on Phys.org
Smazmbazm said:

Homework Statement



Given a vector field

[itex]F(x,y,z) = (yz + 3x^{2})\hat{i} + xz\hat{j} + xy\hat{k}[/itex]

Calculate the line integral

[itex]∫_{A}^{B}F\bullet dl[/itex]

where A = (0,1,3) and B = (1,2,2)

Homework Equations



Right, first of all, what is dl ? I've gone over all my course notes and don't see dl anywhere. I managed to find on this site that dl = (dx, dy, dz). Is that the case?

If so, my attempt at the solution is

[itex]∫_{A}^{B}(yz + 3x^{2})dx + xzdy + xydz[/itex]

Now what? I'm not really sure how to set the intervals from those 2 points in space. Am I supposed to do something like

[itex]∫_{0}^{1}(yz + 3x^{2})dx + ∫_{1}^{2}xzdx +∫_{3}^{2}xydz[/itex] ?

Thanks for any assistance.

No, dl isn't equal to (dx,dy,dz) in general. dl depends on the path you are integrating along. They didn't give you a path. Any idea why not?
 
Smazmbazm said:
Here is the whole question

http://imgur.com/KGI28pJ

[PLAIN]http://imgur.com/KGI28pJ[/QUOTE]
Just follow the questions in sequence. Use Gradient theorem. Like Gauss's and Stoke's theorems,
they are fancy version of FTC in Calc.
 
Last edited by a moderator:
Sure. But I don't understand what dl is in this question. How does one determine dl and also what are the limits of integration..? What I find confusing is distinguishing between what dl, ds, and dr all mean in various contexts. Such as

[itex]∫_{C}F.ds[/itex]

[itex]∫^{B}_{A}F.dl[/itex]

and

[itex]∫_{C}F.dr[/itex]

what are the differences between all these...?
 
Smazmbazm said:
Sure. But I don't understand what dl is in this question. How does one determine dl and also what are the limits of integration..?

You get ##\vec{dl}## from the parametrisation of your path. So what path are you going to take? Why do you think the question has not specified a path?
 
Smazmbazm said:
Yea ok, I figured that out. So the path I got, following http://tutorial.math.lamar.edu/Classes/CalcIII/LineIntegralsPtI.aspx was r(t) = <t, t+1,3-t> and after evaluating the whole expression I got an answer of 5. Dunno if that's right because we aren't given answers to our questions for some silly reason -.-
Yes, that's right, but what justifies using the straight line parametrisation?
 
Is that because it's a conservative field and calculations are therefore path independent?
 
Smazmbazm said:
Is that because it's a conservative field and calculations are therefore path independent?

Exactly.