Line Tangent to following surface

mopar969
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What is the solution to:
What is the equation of a line tangent to the following surface z=6-(4x^2)-(y^2) at the point (5,3,-103)
 
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hi mopar969! :wink:

show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
You ask for the equation of a line tangent to a surface. There will be a whole plane tangent to the surface and any line lying in that plane will be tangent to the surface. Do you know how to find the tangent plane to a surface?
 
I thought that maybe I need to find the normal vector first to start this problem but I am not sure please help.
 
that would certainly do it! :smile:
 
If a surface is described by f(x,y,z)= constant, then \nabla f is perpendicular to the surface.
 
Let z = f(x,y). z is "three-dimensional" so its tangent must be "two-dimensional".

T: z -z0 = . . . you finish the rest.
 
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