- #1
ch2kb0x
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Homework Statement
dy/dx + ytanx = secx, y(pi) = 1
Homework Equations
I(x) = e^integral P(x)dx
Integral Q(x)e^integral P(x)dx
y=e^-integral P(x)dx (integral Q(x)e^integral P(x)dx + C)
(sorry, it is a bit messy, I don tknow how to use the math symbols yet)
The Attempt at a Solution
dy/dx + ytanx = secx, where P(x) = tanx, Q(x) = secx
ytanx - secx + dy/dx = 0
I(x) = e^Integral tanx = e^-ln(cosx)
Integral Q(x)e^integral P(x)dx = Integral (1/cosx) e^-ln(cosx) dx.
^^this is where I am stuck, either I did something wrong in the beginning, and/or it has to be integrated by parts. I only know how to do the "tabular table" method for parts, so if my calculations were right to that point, could somebody help me through the rest of the problem. thanks :(