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rad0786
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Let U and V denote, respectively, the spaces of even and odd polynomials in Pn. Show that dimU + dimV = n+1 [Hint: Consider T: Pn ---> Pn where T[p(x) - P(-x) ]
So where to begin?
I thought that i should let p(x) = a + a0x + a2x^2 + ... + anX^n
So if U is the space of even polynomials, and let n be even, then U is the set of polynomials p(x) = a + a0x + a2x^2 + ... + anX^n then dimU = n
Then I am lost here, however, I thought id use the transformation... T: Pn ---> Pn where T[p(x) - P(-x) ] (by the way, is that transformation T: U ---> V well if it is.. i assumed it as and continuted)
Applying that transformation, you get
a + a0x + a2x^2 + ... + anX^n - [ a + a0(-x) + a2(-x)^2 + ... + an(-X)^n] = 2a0x + ... + 2anX^n
Can somebody help me?
Thanks
So where to begin?
I thought that i should let p(x) = a + a0x + a2x^2 + ... + anX^n
So if U is the space of even polynomials, and let n be even, then U is the set of polynomials p(x) = a + a0x + a2x^2 + ... + anX^n then dimU = n
Then I am lost here, however, I thought id use the transformation... T: Pn ---> Pn where T[p(x) - P(-x) ] (by the way, is that transformation T: U ---> V well if it is.. i assumed it as and continuted)
Applying that transformation, you get
a + a0x + a2x^2 + ... + anX^n - [ a + a0(-x) + a2(-x)^2 + ... + an(-X)^n] = 2a0x + ... + 2anX^n
Can somebody help me?
Thanks